Answer:
The wall is 90 meters wide.
Step-by-step explanation:
1. set up and solve a proportion to find the value of w like this:
1cm=6cm
15m=wm
2. cancel out the like units on both sides of the equation
1=6
15=w
3. Equate the cross products, and then solve for w:
1*w=15*6
w=90 The actual width of the wall is 90 meters.
It’s is 20,0000 but it think that’s wrong
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
5√2 is as simple as it gets
5√2 ≈ 7.071068
Step-by-step explanation:
One simplifies radical expressions by removing from under the radical any squares that might be there. 2 is a prime number, so has no square factors. The simplest form of this radical expression is the one given:
5√2
Your calculator can tell you the value of this irrational number is about ...
5√2 ≈ 7.071068
Answer:
If M<6=72
Step-by-step explanation:
Then What is M
M=72/6 =12
so M<7=12 by 7=84
therefoe M<7=84
