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tatyana61 [14]
3 years ago
12

A scientist studying bacteria begins with 20 cells. The bacteria population doubles every hour. Complete the table below to dete

rmine after how many hours there will be more than 500 bacteria cells. Time (hours) Number of bacteria cells 0 20 1 40 2 80 3 4 5 6 Write an exponential function to model this situation. Predict the bacteria population after 11 hours.
Mathematics
2 answers:
Reil [10]3 years ago
3 0
The bacteria population will be 40,960 in 11 hours
Artyom0805 [142]3 years ago
3 0

Answer:

1)

t=5 hours.

2)

40960 cells.

Step-by-step explanation:

A scientist studying bacteria begins with 20 cells.

The bacteria population doubles every hour.

Let P(t) determines the population of the bacteria in 't' hours.

Hence, by the given information our function P(t) is modeled as:

P(t)=20\times 2^t

Now, we have to find the value of 't' such that:

P(t)>500

i.e.

20\times 2^t>500\\\\\\2^t>\dfrac{500}{20}\\\\2^t>25

on taking logarithmic function on both side we get:

t\log 2>\log 25\\\\t>\dfrac{\log 25}{\log 2}\\\\t>4.64

i.e. after 5 hours the population of the bacteria will exceed 500.

Now we have to find the value of function P(t) when t=11.

i.e.

P(11)=20\times 2^{11}\\\\P(11)=20\times 2048\\\\P(11)=40960

Hence , the population of bacteria after 11 hours is:

40960 cells.

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5 0
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200 σ j=1 2j( j 3) describe the steps to evaluate the summation. what is the sum?
ziro4ka [17]

The sum of the equation is  = 5494000.

<h3>What does summation mean in math?</h3>

The outcome of adding numbers or quantities mathematically is a summation, often known as a sum. A summation always has an even number of terms in it. There may be just two terms, or there may be 100, 1000, or even a million. Some summations include an infinite number of terms.

<h3>Briefing:</h3>

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

<h3>Calculation according to the statement:</h3>

\sum_{j=1}^{200} 2 j(j+3)

simplifying them we get:

\sum_{j=1}^{200} 2 j^{2}+6 j

Split the summation into smaller summations that fit the summation rules.

\sum_{j=1}^{200} 2 j^{2}+6 j=2 \sum_{j=1}^{200} j^{2}+6 \sum_{j=1}^{200} j

\text { Evaluate } 2 \sum_{j=1}^{200} j^{2}

The formula for the summation of a polynomial with degree 2

is:

\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}

Substitute the values into the formula and make sure to multiply by the front term.

(2)$$\left(\frac{200(200+1)(2 \cdot 200+1)}{6}\right)$$

we get: 5373400

Evaluating same as above : 6 \sum_{j=1}^{200} j

we get: 120600

Add the results of the summations.

5373400 + 120600

= 5494000

The sum of the equation is  = 5494000.

To know more about  summations visit:

brainly.com/question/16679150

#SPJ4

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