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2 years ago

Will mark brainliest if right and you show your work!

Mathematics

1 answer:

yarga [219]2 years ago

4 0

Answer:

the gcm or greatest common factor is <u>3xy</u> :)

Step-by-step explanation:

Factor 18x2y3−6xy2+3x3y

18x2y3+3x3y−6xy2

=3xy(6xy2+x2−2y)

3xy(6xy2+x2−2y)

3xy

HOPE THIS HELPS

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M∠1=28°, m∠6=65°, m∠5=65°. Find m∠MAX

kirill115 [55]

Answer:

<MAX = 93

Step-by-step explanation:

Since <MAX is technically <1 + <5, we know that <1 is 28 and <5 is 65. We can add both of these angles up to solve for <MAX, which is 28 + 65 = 93.

5 0

3 years ago

The mean of 6 numbers is 8.

shutvik [7]

Answer: 8

Step-by-step explanation:

Given

Mean of the numbers is 8

If the ratio is 1:1:2:2:3:3

Suppose the numbers are $x, x, 2x, 2x, 3x, 3x$

Write the mean of the numbers

$\Rightarrow \dfrac{x+x+2x+2x+3x+3x}{6}=8\\\\\Rightarrow \dfrac{12x}{6}=8\\\\\Rightarrow x=4$

So, the numbers are $4, 4, 8,8 ,12,12$

As the total numbers are even, median is the sum of the middle values

$\Rightarrow \text{Median=}\dfrac{8+8}{2}\\\\\Rightarrow \text{Median=}8$

8 0

2 years ago

The circle graph shows a family budgets it’s annual income.if the total annual income is 140,000, what amount is budgeted for au

emmasim [6.3K]

Answer: The amount budgeted for Auto Expenses is $18,200

Step-by-step explanation:

13 Percent of $140,000 is $18,200

0.13 times 140,000 :-)

5 0

2 years ago

Mrs. Johnson walks 16 miles in 4 hours.

Irina-Kira [14]

I think the answer is no

3 0

1 year ago

Please show your work and explain it.

Maru [420]

Answer:

$f(x)=\dfrac{x+2}{2(x-2)}$

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

$\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}$

Next we factor what we can so we can further simplify the rest of the equation:

$=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\$

We can now cancel out (x+2)

$=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}$

Next we factor out even more:

$=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}$

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

$=\dfrac{(x+2)(1)}{(x-2)(2)}$

And we can now simplify it to:

$=\dfrac{x+2}{2(x-2)}$

6 0

2 years ago