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Law Incorporation [45]
3 years ago
5

If 1 euro is priced at $1.25 and if 1 euro will also buy 88 Japanese yen (€1 = ¥88), in equilibrium, with no arbitrage opportuni

ties, how much is the cross rate between the yen and the dollar (yen per dollar exchange rate)?
Mathematics
1 answer:
Alborosie3 years ago
5 0

Answer:

So the exchange rate is that each dollar is worth 70.4 yens.

Step-by-step explanation:

We have that:

1 euro is priced at $1.25

1 euro will also buy 88 Japanese yen

This also means that:

$1.25 is priced at 88 Japanese yen

How much is the cross rate between the yen and the dollar (yen per dollar exchange rate)?

How much yens is 1 dollar?

This can be solved by a simple rule of three.

$1.25 - 88 yen

$1 - x yen

1.25x = 88

x = \frac{88}{1.25}

x = 70.4

So the exchange rate is that each dollar is worth 70.4 yens.

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Which statement correctly describes the end behavior of y = 3x8 + 5x2 +2x - 1
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Answer:

C)  The graph rises to the left and rises to the right.

Step-by-step explanation:

The highest expone tis even and it's coefficient is positive

therefor

The graph rises to the left and rises to the right.

5 0
2 years ago
Plz help meee Thank you very much for whoever helps
ratelena [41]

Answer:

70

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Rewrite the subtraction as addition 3- (-10)
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<span>Rewrite the subtraction as addition 3- (-10)

= 3 + 10</span>
4 0
3 years ago
Sharon is twice as old as Brian, and in 5 years the sum of their ages will be 25 years. Find their present ages.
Vinil7 [7]
Sharon's age= 2x
Brian's age= x

(2x-5)+(x-5)= 25
3x-10=25
3x=15
x=5
Brian is 5 years old and Sharon is 10

3 0
3 years ago
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
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