$72.
20% of 60 is 12
$12 + $60 = $72
8^2 /2+5(15-7)
=64/2+75-35
=32+40
=72
<span><span>3<span>(<span>5−9</span>)</span></span>+<span>4<span>(<span>4−9</span>)
</span></span></span><span>=<span><span><span>(3)</span><span>(<span>−4</span>)</span></span>+<span>4<span>(<span>4−9</span>)
</span></span></span></span><span>=<span><span>−12</span>+<span>4<span>(<span>4−9</span>)
</span></span></span></span><span>=<span><span>−12</span>+<span><span>(4)</span><span>(<span>−5</span>)
</span></span></span></span><span>=<span><span>−12</span>+<span>−20
</span></span></span><span>=<span>−32
</span></span><span><span>10<span>(<span>9−18</span>)</span></span>−<span>32
</span></span><span>=<span><span><span>(10)</span><span>(<span>−9</span>)</span></span>−<span>32
</span></span></span><span>=<span><span>−90</span>−<span>32
</span></span></span><span>=<span><span>−90</span>−9
</span></span><span>=<span>−<span>99
</span></span></span><span><span>−<span>12<span>(<span>5−7</span>)</span></span></span>−<span>10<span>(<span>2−5</span>)
</span></span></span><span>=<span><span><span>(<span>−12</span>)</span><span>(<span>−2</span>)</span></span>−<span>10<span>(<span>2−5</span>)
</span></span></span></span><span>=<span>24−<span>10<span>(<span>2−5</span>)
</span></span></span></span><span>=<span>24−<span><span>(10)</span><span>(<span>−3</span>)
</span></span></span></span><span>=<span>24−<span>(<span>−30</span>)
</span></span></span><span>=<span>54</span></span>
You could write 6/15 as a decimal 0.40.
Therefore .48>.40
I think the answer is A. 3.
B. no, to big a number
C. no, to small a number
D. no, again, too big a number.
Have a nice day and hope this helps!
Answer:
Approx 2.61 years.
Step-by-step explanation:
Given that you decide to put $5,000 in a savings account to save for a $6,000 down payment on a new car.
That means A=6000 and P=5000
If the account has an interest rate of 7% per year and is compounded monthly,
Then r=7%= 0.07 and n=12 (monthly)
Now we need to find about how long does it take until you have $6,000 without depositing any additional funds.
So let's plug these values into compound interest formula and fine time t
![\ln\left(1.2\right)=12t\ ln[tex]\frac{\ln\left(1.2\right)}{12\ln\left(1.00583333333333\right)}=t](https://tex.z-dn.net/?f=%5Cln%5Cleft%281.2%5Cright%29%3D12t%5C%20ln%5Btex%5D%5Cfrac%7B%5Cln%5Cleft%281.2%5Cright%29%7D%7B12%5Cln%5Cleft%281.00583333333333%5Cright%29%7D%3Dt)
\left(1.00583333333333\right)[/tex]
Hence answer is approx 2.61 years.
