Answer:
a
Step-by-step explanation:
hope this helps
;)
D. y = 3x + 2
Check (-4, -10)
-10 = 3(-4) + 2
-10 = -12 + 2
-10 = -10 :)
Check (-3, -7)
-7 = 3(-3) + 2
-7 = -9 + 2
-7 = -7 :)
Check (-2, -4)
-4 = 3(-2) + 2
-4 = -6 + 2
-4 = -4 :)
Check (-1, -1)
-1 = 3(-1) + 2
-1 = -3 + 2
-1 = -1 :)
Check (0, 2)
2 = 3(0) + 2
2 = 0 + 2
2 = 2 :)
Answer:
It will
Step-by-step explanation:
A meter is about 3,3 feet so 2,1 meters is 6,8 feet meaning that yes it will fit.
The distance is increasing at a rate that is the speed of the plane multiplied by the cosine of the angle between its flight path and the direct line to the radar station. That cosine is 4/√(3²+4²) = 4/5, so the distance is increasing at
440 mi/h × 4/5 = 352 mi/h
Answer:
∂u/∂xi = i·cos(sn)
Step-by-step explanation:
For u = sin(v), the partial derivative of u with respect to xi is ...
∂u/∂xi = cos(v)·∂v/xi
In this case, v=sn, and ∂sn/∂xi = i, so the derivatives of interest are ...
∂u/∂xi = i·cos(sn)
