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2 years ago

75% increase followed by 50% decrease is it greater than to original

Mathematics

1 answer:

IceJOKER [234]2 years ago

7 0

Answer:

Set original amount = x

After a 75% increase, it would become

x + 75%x = x + 0.75x = x(1 + 0.75) = 1.75x

After a 50% decrease, it would become

1.75x - 50%(1.75x) = 1.75x - 0.5(1.75x) = 1.75x - 0.875x = 0.875x = $\frac{7}{8} x$

Because $\frac{7}{8} x$ is less than x, the new amount would be less than the original.

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For the equation --4y = 8x, what is the constant of variation?

larisa86 [58]

Answer: 1) B is correct, constant of variation is -2.

Step-by-step explanation:

Direct variation states that a relationship between the two variables. we say y varies directly as x

i.e, or y =kx.................[1] ; where k is the constant of variation.

Given the equation:

Divide both sides by -4 we get;

Simplify:

.......[2]

On comparing equation [2] with [1] we get;

k = -2

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3 years ago

Anita is making a curtain to surround a table. She bought 3 1/4 yards of fabric. Her total cost was $13. What was the cost per y

Ratling [72]

3.25y=13. Isolate y by dividing both sides of the equation by 3.25. So 3.25y/3.25=13/3.25. Your answer is therefore 13/3.25, or 4

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3 years ago

Read 2 more answers

X 5. 2, for x = 10 Pls give answer!!!!

mestny [16]

100

if x=10 10 times 5 equals 50 times 2 is 100

6 0

3 years ago

If you help me with this fast I will brain you. Thanks.

irakobra [83]

Answer:

-2 and -6 is the correct answer

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3 years ago

Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60

anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

$L=5W-60$ (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

$Area=W*L=W*(5W-60)$ (Equation #2)

Since the Area of the yard is $800 ft^2$ , then equation #2 turns into:

$800=W*(5W-60)$

Now, we rearrange this equation:

$800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0$

We can divide the equation by 5 :

$W^2-12W-160=0$

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since $(-20)*8=160$ and $-20+8=-12$ . The equation factorised looks like this:

$(W-20)(W+8)=0$

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

$5*20-60=40$

Therefore, the dimensions of the yard are W=20ft and L=40ft.

7 0

3 years ago