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Oliga [24]
2 years ago
7

A truck's distance from a warehouse, d , (measured in miles) is modeled by the formula d = t 2 + 70 t where t represents the num

ber of hours since the truck left the warehouse. The truck's destination is 429.75 miles away. How many hours will it take the truck to reach its destination?
Mathematics
1 answer:
miskamm [114]2 years ago
4 0

Answer:5.67 h

Step-by-step explanation:

Given

Distance is given by

d=t^2+70 t  , t is in hours

Truck destination is 429.75 miles away

i.e. substitute d=429.75 miles

t^2+70t-429.75=0

Roots of Quadratic Equation can be found  out by

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using this

t=\frac{-70\pm \sqrt{70^2+4\times 1\times 429.75}}{2\times 1}

t=\frac{-70\pm \sqrt{6619}}{2}

t=\frac{-70\pm 81.357}{2}

t=5.67 hr

Neglecting negative t

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Solve the given system of equations utilizing either the substitution or addition method.
Nataly [62]

Answer:

Value of x=4 and y=-13/3

Step-by-step explanation:

We need to solve the systems of equations

5x+3y=7 \ and \ \frac{3}{2}x-\frac{3}{4}y =9\frac{1}{4}

Solving using substitution method:

Let:

5x+3y=7---eq(1) \\ \frac{3}{2}x-\frac{3}{4}y =9\frac{1}{4}---eq(2)

Find value of x from eq(1) and put in eq(2)

5x+3y=7\\5x=7-3y\\x=\frac{7-3y}{5}

Put value of x in eq(2)

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Now, finding value of x by putting value of y in eq(1)

x=\frac{7-3y}{5}\\x= \frac{7-3(-\frac{13}{3}) }{5}\\x=\frac{7+13}{5}\\x=\frac{20}{5}\\x=4

So, Value of x=4 and y=-13/3

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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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In the diagram below,

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