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3 years ago

Side lengths of a triangle 5x-1 and 4x+1

1 answer:

4 0

You aren't sharing much information (no directions??).

If your triangle is a right triangle AND 5x-1 and 4x+1 represent the lengths of the 2 shortest sides, then the Pyth. Theorem tells us that

(5x-1)^2 + (4x+1)^2 = (hypotenuse length)^2.

We know that this could not be an equilateral triangle, because 5x-1 differs from 4x+1.

This could be an isosceles triangle if the third side were either 5x-1 or 4x+1.

Please be more specific about what you're supposed to do here.

You might be interested in

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

Dose anybody know this need the answer asp

Lynna [10]

Answer:

I show you the graph in the file

hope it help!

4 0

3 years ago

A number minus the product of 36 and its reciprocal is less than zero. Find the numbers which satsify this condition

svetlana [45]

Answer:

A number minus the product of

and its reciprocal is less than zero. Find the numbers which satisfy this condition.

AAny number less than

−

or between

and

BAny number between

−

and

CAny number less than

DAny number between

and

Solution

Let the number be x

Then

−

(

)

≤

⇒

≤

⇒

≤

⇒

≤

⇒

−

≤

Step-by-step explanation:

5 0

2 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago

9. Find the measure of angle a 36° 57°

masha68 [24]

Answer:

no clue bro

Step-by-step explanation:

3 0

3 years ago