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11Alexandr11 [23.1K]
3 years ago
8

Side lengths of a triangle 5x-1 and 4x+1

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0
You aren't sharing much information (no directions??).

If your triangle is a right triangle AND 5x-1 and 4x+1 represent the lengths of the 2 shortest sides, then the Pyth. Theorem tells us that

(5x-1)^2 + (4x+1)^2 = (hypotenuse length)^2.

We know that this could not be an equilateral triangle, because 5x-1 differs from 4x+1.

This could be an isosceles triangle if the third side were either 5x-1 or 4x+1.

Please be more specific about what you're supposed to do here.

You might be interested in
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
2 years ago
Dose anybody know this need the answer asp
Lynna [10]

Answer:

I show you the graph in the file

hope it help!

4 0
3 years ago
A number minus the product of 36 and its reciprocal is less than zero. Find the numbers which satsify this condition​
svetlana [45]

Answer:

A number minus the product of

4

and its reciprocal is less than zero. Find the numbers which satisfy this condition.

AAny number less than

−

2

or between

0

and

2

BAny number between

−

2

and

2

CAny number less than

2

DAny number between

0

and

2

Solution

Let the number be x

Then

x

−

(

4

×

1

x

)

≤

0

⇒

x

≤

4

x

⇒

x

2

≤

4

⇒

|

x

|

≤

2

⇒

−

2

≤

x

≤

2

Step-by-step explanation:

5 0
2 years ago
Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate
kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality x^{2}-5x+4\leq 0. To do that, factorize, then we have that (x-4)(x-1)\leq 0. This implies that

x-1\leq 0\, \text{and}\, x-4\geq 0

or

x-1 \geq 0\, \text{and}\, x-4\leq 0

In the first case the solution is the empty set \emptyset. In the second case the solution is the interval 1\leq x \leq 4. Now we have that

A=[1,4]

B=(3,5)

C=(3,4].

To show that A\cap B\subseteq C consider x\in A\cap B. Then 1\leq x \leq 4\, \text{and}\, 1, this implies that 3, then x\in C. Now, to show that C\subseteq A\cap B consider x\in C, then 3, then 1\leq x \leq 4\, \text{and}\, 3, then x\in [1,4] \, \text{and}\, x\in (3,5), this implies that x\in A\cap B.

Observe the image below.

7 0
3 years ago
9. Find the measure of angle<br> a<br> 36°<br> 57°
masha68 [24]

Answer:

no clue bro

Step-by-step explanation:

3 0
3 years ago
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