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kondor19780726 [428]
3 years ago
8

Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru

n at 6 mph and walk 4 mph, how long will he be from home?
Mathematics
1 answer:
jenyasd209 [6]3 years ago
7 0

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time (t_{T}) that Keenan will be from home is the sum of run (t_{R}), hang out (t_{H}) and walk times (t_{W}), measured in hours:

t_{T} = t_{R}+t_{H}+t_{W}

If Keenan runs and walks at constant speed, then equation above can be expanded:

t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}

Where:

x_{R}, x_{W} - Run and walk distances, measured in miles.

v_{R}, v_{W} - Run and walk speeds, measured in miles per hour.

Given that x_{R}=x_{W} = 2.5\,mi, v_{R} = 6\,\frac{mi}{h}, v_{W} = 4\,\frac{mi}{h} and t_{H} = 0.75\,h, the total time is:

t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }

t_{T} = 1.792\,h (1\,h\,48\,m)

Kennan will be from home approximately an hour and 48 minutes.

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Answer:

x = 6

Step-by-step explanation:

Step 1: Write equation

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Step 2: Solve for <em>x</em>

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Step-by-step explanation:

Given a directed line segment from point A to B.

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The point which is closest to the point B.

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Here, to find the point closest to B we need to find the distances PB, QB, RB and SB.

We can see the sum of ratio 3:4, 4:3, 2:5 and 5:2 is 7.

Let the distance between A and B be 7 units.

Now, the distances can be found easily.

PB = \dfrac{4}{7}\times 7 = 4\ units

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The point which has the minimum distance from point B, will be nearest to B.

We can clearly observe that SB is the minimum distance.

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