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ioda
3 years ago
9

1. We have 50 pounds of dog food to last for 10 days. Each day we use the same

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer:

5 pounds

Step-by-step explanation:

50 pounds of dog food divided by 10 days = 5 pounds per day for 10 days.

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To get into shape, Miles ran for 1 minute on Monday, 3 minutes on Tuesday, 6 minutes on Wednesday, and 10 minutes on Thursday. I
Eduardwww [97]

Answer:

15 minutes??

I guess?

Step-by-step explanation:

Im really not sure

There's a pattern!!

You just need to count how many numbers passed by!

Clear?

3 0
3 years ago
Plz help me i dotn know this
miv72 [106K]

Answer:

it's D. I think 105 cubic feet

3 0
3 years ago
Read 2 more answers
Ok need help this is the question :Use the Pythagorean theorem to write an equation for the distance Jane's trainer bikes.
IRINA_888 [86]

Answer:

<em>Jane traveled 8 miles farther then her trainer</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

c^2=a^2+b^2

Where

c = Hypotenuse or largest side

a,b = Legs or shorter sides

Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.

Her total distance traveled is 16 + 12 = 28 miles

Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.

We can calculate the length of his route as:

c=\sqrt{16^2+12^2}

c=\sqrt{256+144}=\sqrt{400}=20

c = 20 miles

The difference between their traveled lengths is 28 - 20 = 8 miles

Jane traveled 8 miles farther then her trainer

8 0
3 years ago
The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of
Oksanka [162]

Given:

<u>In July:</u>

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

<u>In August:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

<u>In September:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

<u>In October:</u>

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

<u>In November:</u>

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

<u>In December:</u>

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

<u>In July,</u>

The difference between the number of days with homework and with no homework = 6-4 = 2

<u>In August,</u>

The difference between the number of days with homework and with no homework = 16-7 = 9

<u>In September,</u>

The difference between the number of days with homework and with no homework = 14-4 = 10

<u>In October,</u>

The difference between the number of days with homework and with no homework = 14-8 = 6

<u>In November,</u>

The difference between the number of days with homework and with no homework = 16-4 = 12

<u>In December,</u>

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

4 0
3 years ago
In a group of 50 patrons, 12 patrons like lattes and espressos, 9 patrons like espressos and cappuccinos, 8 patrons like lattes
quester [9]
I used a Venn Diagram which I attached.
Think of it as a flower and work your way from the center out to the doubles (two kinds of coffee) and finally the singles (only one kind of coffee)
I place 4 in the center to represent the people that like all three.
Then I put 8 in the Latte Espresso group since they along with the 4 who like all three, make up the 12 who like lattes and espresso.  I put 4 in the Latte & Cappuccino group since they and the 4 who like all coffees, make up the 8 who like lattes and cappuccinos. And then I put 5 in the Espresso Cappuccino group who along with the 4 in the middle make up the 9 who like both of those.
In all 20 like lattes and my latte circle already has 16 so I added 4 (who only like lattes).  22 like espresso and I have accounted for 17 (8+4+5) so that means there are 5 who only like espresso.  Finally out of the 17 who like cappuccinos, 13 are already accounted for so I will add 4 who like only cappuccinos.
Since there are 50 people and I can account for 34 of them (add all the numbers in all three circles), there must be 50-34 people who don't like any.  The correct answer is d.16
Download docx
3 0
3 years ago
Read 2 more answers
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