All categories

2 years ago

State if the two triangles are congruent. If they are, state how you know?

Mathematics

1 answer:

oee [108]2 years ago

8 0

They are congruent because the right angles are congruent, the dashed lines are congruent, and the angles that are attached are congruent. The attached angles are congruent because they share two sides

You might be interested in

16. Construct 3 equations starting with x = 5.

strojnjashka [21]

TO FIND:  construct 3 equation starting with x=5?

SOLUTION: 

The equation is in the form of variable and constant equating.

Let the equation be x=5.

TO CREATE AN EQUATION,

FIRST WE ADD 5 BOTH SIDe,

x + 5=5+5

=x + 5=10

SECOND WE SUBRACT 5 BOTH SIDE,

x — 5=5—5

=x—5=0

THIRD WE MULTIPLY 5 BOTH SIDE,

5x=5×5

=5x=25

well u got the answer!

3 0

3 years ago

Find the value of the expression 4a^4 − 2b^2 + 40 when a = 2 and b = 7

Effectus [21]

Answer:6

Step-by-step explanation:

4(2)^4 − 2(7)^2 + 40

4(16)-2(7)^2+40

64-2(49)+40

64-98+40

-34+40

7 0

2 years ago

Read 2 more answers

I need help plez and thanks

Brilliant_brown [7]

He has a total of $58.19.
1 day = $2.74

58.19/2.74
21.24

You can't have 21.2 days, so you need to round down to 21.

Jim can buy lunch for 21 days before he runs out of money on his account.

3 0

3 years ago

Read 2 more answers

15 points ! Find m < RQP

Phoenix [80]

Answer:

<RQP = 70°

Step-by-step explanation:

<RQP = 1/2 (140)

<RQP = 70°

4 0

2 years ago

Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a

cluponka [151]

Answer:

B. Train B

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

$\text{Distance}=\text{Speed*Time}$

$\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}$

$\text{Distance traveled by train A}=90\times 3{\text{ miles}$

$\text{Distance traveled by train A}=270{\text{ miles}$

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

$\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}$

$\text{Distance traveled by train B}=70\times 5 \text{ miles}$

$\text{Distance traveled by train B}=350\text{ miles}$

Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.

5 0

3 years ago