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Leno4ka [110]
3 years ago
12

U

Mathematics
1 answer:
Ivanshal [37]3 years ago
3 0

Answer:

The number missing on the number line is<em> </em><em>(7)!</em>

There should be <em>(2)</em> dots above the number 4.

There should be <em>(4)</em> dots above the number 6.

A good title for the dot plot is;

(<em>Age you lost your first tooth!!!)</em>

<em></em>

-- <u>I hope this helped!!Could i get brainliest if i'm correct please?--</u>

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100 POINTS GEOMETRY QUESTION PLEASE ANSWER !!!!!!
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

ABC have sides: 5, 7 and 10

5^2 + 7^2 = 25+47 = 72 < 10^2

so triangle ABC is obtuse

JKL has sides: 12, 35 and 37

12^2 + 35^2 = 144 + 1225 = 1369 = 37^2

so triangle JKL is right-angled

PQR has sides 12, 10 and 16

12^2 + 10^2 = 144 + 100 = 244 > 16^2

so triangle PQR is acute

5 0
3 years ago
Read 2 more answers
What is the area?<br> 5 yd<br> 2 yd<br> 10 yd<br> square yards
pickupchik [31]
The area in yards is 5
5 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
Help!
dsp73
Your answer in scientific notation is 2.355 * 10^14
6 0
3 years ago
Daniel has lunch at a restaurant and the cost of his meal is $49.00, because of the service, he wants to leave a 5% tip. what is
yuradex [85]
49*1.05= $51.45

Hope it helped
8 0
3 years ago
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