Answer
Step-by-step explanation:
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The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
6 slices
Step-by-step explanation:
The full pizza is 12 pieces. Divide 12 by 4 to find out how much she ate on Thursday. 1/4 of 12 is 3 so she ate 3 slices on Thursday. Subtract 3 from 12 to find out how much was left for the next day. There were 9 slices the next day. Next, divide 9 by 3 to find out what 1/3 of 9 is. 1/3 of 9 is 3 so subtract 3 from the 9 slices. 6 slices are the original pizza remain.
Answer:
Step-by-step explanation:
z = 3
2y + z = 1
2y + 3 = 1 {substituting z =3}
2y = 1 -3
2y = -2
y = - 2/2
y = -1
2x +3y +2z = 13
2x + 3 * (-1) + 2*3 = 13 { {substituting z =3} and y = -1}
2x -3 + 6 =13
2x + 3 = 13
2x = 13 - 3
2x= 10
x = 10/2
x = 5
Answer:
11, 14, 17, 20
Step-by-step explanation:
An arithmetic sequence has a common difference d between consecutive terms.
Consider 2, 6, 18, 54
6 - 2 = 4, 18 - 6 = 12, 54 - 18 = 36 ← no common difference, not arithmetic
Consider 3, 6, 12, 24
6 - 3 = 3, 12 - 6 = 6, 24 - 12 = 12 ← no common difference, not arithmetic
Consider 11, 14, 17, 20
14 - 11 = 3, 17 - 14 = 3, 20 - 17 = 3 ← common difference of 3, so arithmetic
Consider 7, 11, 13, 18
11 - 7 = 4, 13 - 11 = 2, 18 - 13 = 5 ← no common difference, not arithmetic
The arithmetic sequence is 11, 14, 17, 20
