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True [87]
3 years ago
14

The first two terms of an arithmetic progression are 27 and 24 respectively. How many terms of the progression are to be added t

o get - 30?
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Answer:

20 terms

Step-by-step explanation:

<u>Given AP with the first two terms:</u>

  • a₁= 27 and a₂=24

<u>Common difference: </u>

  • d= 24-27 = -3

<u>To find </u>

  • n for which Sₙ= -30
<h3>Solution</h3>
  • Sₙ = 1/2*n*(a₁+aₙ) =
  • 1/2n(a₁+a₁+(n-1)d) =
  • 1/2n(27+27+(n-1)(-3))=
  • 1/2n(54 - 3n + 3) =
  • 1/2n(57 - 3n)

<u>Since Sₙ = -30</u>

  • 1/2n(57 - 3n) = -30
  • 57n - 3n² = -60
  • 19n - n²- 20 = 0
  • n² -19 n -20= 0

<u>Solving the quadratic equation we get:</u>

  • n =20

So the sum of 20 terms will add up - 30

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The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
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