Pls whats the solution to this question.(x-1÷x)^6.and also solve with full workings.

Mathematics

1 answer:

Harrizon [31]3 years ago

5 0

$\huge\red{\boxed{\tt{\colorbox{pink}{ANSWER:}}}}$

$\frac{ {x}^{12} - {6x}^{10} + {15x}^{8} - {20x}^{6} + {15x}^{4} - {6x}^{2} + 1 }{ {x}^{6} }$

$\huge\red{\boxed{\tt{\colorbox{pink}{Solution:}}}}$

$(x - 1 \div x) {}^{6}$

$\frac{x {}^{12} - {6x}^{10} + {15x}^{8} - {20x}^{6} + {15x}^{4} - {6x}^{2} + 1 }{ {x}^{6} }$

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<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

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$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

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