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vodka [1.7K]
3 years ago
13

Are 2/5 4/10 6/15 and 8/20 proportional?

Mathematics
2 answers:
Over [174]3 years ago
5 0
Yes, since you can multiply 2/5 numerator and denominator to get the rest of the fractions, it makes them all equivalent.
luda_lava [24]3 years ago
4 0

Answer:yes they are

Step-by-step explanation:

2/5=4/10

2/5=2/5

-----------

4/10=6/15

2/5=2/5

--------------------

6/15=8/20

2/5=2/5

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if tom spins the spinner 80 times work out an estimate for the number of times the spinner will land on 3 please help me
NNADVOKAT [17]

Answer:

The estimated number of times the spinner will land on 3 is 20.

Step-by-step explanation:

The complete question is:

A four-sided spinner is provided. If Tom spins the spinner 80 times then work out an estimate for the number of times the spinner will land on 3.

Solution:

Assume that the four-sided spinner is unbiased.

That is all the four outcomes are equally likely to be selected.

The probability that the spinner lands on any of the four numbers is:

P(1) = P (2) = P (3) = P (4) = 0.25

It is provided that Tom spins the spinner <em>n</em> = 80 times.

The spinner can land on any of the four numbers independently.

The random variable <em>X</em>, defined as the number of times the spinner lands on 3, follows a Binomial distribution with parameters <em>n</em> = 80 and <em>p</em> = 0.25.

The expected value of <em>X</em> is:

E(X)=np

        =80\times 0.25\\=20

Thus, the estimated number of times the spinner will land on 3 is 20.

7 0
2 years ago
Solve for x.<br> 3.3x = 29.04<br> es<br> A)<br> 8.0<br> B)<br> 8.2<br> .<br> 8.6<br> D)<br> 8.8
LenKa [72]

Answer:

The answer is D

Step-by-step explanation:

I just used an algebra calculator

5 0
3 years ago
A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or an 8? Round to nea
Viktor [21]

Answer: 0.476

Step-by-step explanation:

Let A = Event of choosing an even number ball.

B = Event of choosing an 8 .

Given, A lottery game has balls numbered 1 through 21.

Sample space: S= {1,2,3,4,5,6,7,8,...., 21}

n(S) = 21

Then, A= {2,4,6,8, 10,...(20)}

i.e. n(A)= 10

B= {8}

n(B) = 1

A∪B = {2,4,6,8, 10,...(20)} = A

n(A∪B)=10

Now, the probability of selecting an even numbered ball or an 8 is

P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}

=\dfrac{10}{21}\approx0.476

Hence, the required probability =0.476

7 0
3 years ago
Last year, your salary was $33,975. This year, your boss tells you your salary will be $34,960. What percent raise (change) did
Pavlova-9 [17]

Answer:

2.9%

Step-by-step explanation:

5 0
3 years ago
Use the figure to find the measures of the numbered angles
tresset_1 [31]
1. 112 degrees
2. 68 degrees
3 0
2 years ago
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