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Juliette [100K]
3 years ago
7

Luis created a spreadsheet of his expenses for three months. Which of Luis's expenses are variable expenses?

Mathematics
1 answer:
ddd [48]3 years ago
6 0

As they vary from month to month, Luis's variable expenses are the utility bill, groceries, clothing and fuel.

Variable expenses is a concept in economics. They are costs that change due to an increase or decrease in the production volume, such as raw material costs.

The variable cost in money is obtained by multiplying, starting from a certain cost, the variable cost in kind by the price of the variable factor. The curves of average variable cost and marginal variable cost are deduced from the curve of variable cost in money according to geometric relationships.

Therefore, as they vary from month to month, Luis's variable expenses are the utility bill, groceries, clothing and fuel.

Learn more about maths in brainly.com/question/21694231

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When born a baby weighed 8.5 pounds and gained 1.6 pounds per week for the first 10 weeks. which of the following functions accu
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Step-by-step explanation:

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8.5 is (b) because it is the starting weight. The baby's weight gain would be represented by (m), because it changes every week.

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(-18x^2+12x-2)*(x^3+12x^2+48x+64)
prohojiy [21]
<h2>Answer:</h2>

-18x^5-204x^4-722x^3-600x^2+672x-128

<h2>Explanation:</h2>

( - 18 {x}^{2}  + 12x - 2)

( {x}^{3}  + 12 {x}^{2}  + 48x + 64)

There are multiple ways to solve this for example the foil method or the box method. I prefer to do the box method.

First we are going to set it up

After we set it up we have to solve it so first we are going to multiply

{x}^{3}  \times  - 18 {x}^{2}  =  - 18 {x}^{5}

We have to add the exponent

- 18 {x}^{2}  \times 12 {x}^{2}  =  - 216 {x}^{4}

- 18 {x}^{2}  \times 48x =  - 864 {x}^{3 }  \\  - 18{x}^{2}  \times 64 =  - 1152 {x}^{2}  \\ 12x \times  {x}^{3}  = 12 {x}^{4}  \\ 12x \times 12 {x}^{2}  = 144 {x}^{3}

12x \times 48x = 576 {x}^{2}  \\ 12x \times 64 = 768x

- 2  \times  {x}^{3}  =  - 2 {x}^{3}  \\  - 2 \times 12 {x}^{2}  =  - 24 {x}^{2}  \\  - 2 \times 48x =  - 96x \\  - 2 \times 64 =  - 128

Now we have to add them

-18x^5 stays because there is nothing to add to

Now we add the rest

-216 {x}^{4}  + 12 {x}^{4}  =  - 204 {x}^{4}

- 864 {x}^{3}  + 144 {x}^{3}  +  - 2 {x}^{3}  = -  722 {x}^{3}

768x - 96x = 672x

And -128 stays the same

- 1152 {x}^{2}  + 576 {x}^{2}  - 24 {x}^{2}  =  - 600 {x}^{2}

The answer is

-18x^5-204x^4-722x^3-600x^2+672x-128

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4 years ago
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