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3 years ago

Write 7 over 21 in simplest form I have a whole page of this to do, please help

Mathematics

2 answers:

valkas [14]3 years ago

6 0

Answer:

1/3

Step-by-step explanation:

To simplify the fraction 7/21 in its simplest form, you first have to find the common factor between the two numbers, which in this case is seven. Next, divide the numerator and denominator by the factor. So...

7÷7=1

21÷7=3

Seven over twenty-one is the same as one-third, or one over three.

erica [24]3 years ago

3 0

Answer:

1/3 is the answer

Step-by-step explanation:

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Black_prince [1.1K]

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Step-by-step explanation:

f(x)=x^2-4x+3

x coordinate: -b/2a

-(-4)/2(1)=4/2=2

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3 years ago

Write the standard form of the equation of each line. <br> y=1/4 x+2

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3 years ago

Read 2 more answers

If x = 8 units, y = 3 units, and h = 2 units, then what is the area

solniwko [45]

Answer:

8 sq.units

Step-by-step explanation:

x= base of triangle= 8units

h= height of triangle= 2 units

area of triangle= 1/2*b*h

=1/2* 8* 2

=8 sq.units

<em>Mark me as brainliest please</em>

7 0

3 years ago

A ride at a park has room for 8 children to ride at once.

djyliett [7]

Answer:

Step-by-step explanation:

45/8=5.625

Since there are .625 children left, we need to add another ride to fill in what's left.

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2 years ago

How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago