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Romashka-Z-Leto [24]
3 years ago
12

I NEED HELP!

Mathematics
2 answers:
Nutka1998 [239]3 years ago
6 0

5 months I think hop this HELPED

adoni [48]3 years ago
4 0

Answer:

the correct answer would be 5 months

Hope this helps (:

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Please help! Correct answer only!
gulaghasi [49]

Answer:

<em>Probability ≈ 0.1071</em>

Step-by-step explanation:

Consider steps below;

Total Possible Outcomes - 8C5,\\\\8! / 5! ( 8 - 5 )!,\\1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 / ( 1 * 2 * 3 * 4 * 5 )( 1 * 2 * 3 ),\\\\6 * 7 * 8 / 6 = Combinations - 56,\\\\

Number Of Outcomes - 6C5,\\\\6! / 5! ( 6 - 5 )!,\\1 * 2 * 3 * 4 * 5 * 6 / ( 1 * 2 * 3 * 4 * 5 ) ( 1 ),\\720 / 120 * 1,\\\\Outcomes - 6

Conclusion ; Solution - 6 / 56 = ( About ) 0.1071\\Hope That Helps!

<em>Solution; Probability ≈ 0.1071</em>

5 0
3 years ago
WILL MARK BRAINLIEST, JUST HELP ME PLS
Luda [366]

Answer:

SAS theorem

Step-by-step explanation:

If \frac{CE}{CB} = \frac{DC}{AC} and m∠ECD = m∠BCA, then the triangles are similar by the SAS theorem.

\frac{EC}{BC} =  \frac{14}{21} = \frac{2}{3}           \frac{DC}{AC} = \frac{18}{27} = \frac{2}{3}

So,  \frac{CE}{CB} = \frac{DC}{AC}  and m∠ECD = m∠BCA because vertical angles are congruent

Therefore ΔECD is similar to ΔBCA by SAS theorem

5 0
2 years ago
Help please help please
meriva
What does it say In the speaker
7 0
3 years ago
Read 2 more answers
Please help asap!!!!!!<br> vvvvvvvvvvvvvvvvvvvvvvvvv question below vvvvvvvvvvvvvvvvvvvvvvvvvvvv
Amanda [17]

Answer:

3 units

Step-by-step explanation:

Translating a segment does not change its length.

It is just moving the segment.

8 0
3 years ago
If janice plays a game once and the probability of getting yellow is 0.24. How many times will the color shown be yellow if she
blsea [12.9K]

Answer: 12

Step-by-step explanation:

Given

The probability of getting yellow color is 0.24

If the no of trials is 50

\text{No. of times yellow color shown(N) is}=p\times \text{no of trails}\\\Rightarrow N=0.24\times 50=12\ \text{times}

Yellow color appears 12 times

3 0
3 years ago
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