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jenyasd209 [6]
3 years ago
15

Slope of -2 passing through the point (-11,16)

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0
Hope this helps! lmk if you need me to explain anything!

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Which expression is equivalent to *picture attached*
DiKsa [7]

Answer:

The correct option is;

4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3  \left (\dfrac{50(51) }{2} \right )

Step-by-step explanation:

The given expression is presented as follows;

\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3  \right )

Which can be expanded into the following form;

\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3  \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left  n^2 + 3  \times\sum\limits _{n = 1}^{50}  n

From which we have;

\sum\limits _{k = 1}^{n} \left  k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}

\sum\limits _{k = 1}^{n} \left  k = \dfrac{n \times (n+1) }{2}

Therefore, substituting the value of n = 50 we have;

\sum\limits _{n = 1}^{50} \left  k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}

\sum\limits _{k = 1}^{50} \left  k = \dfrac{50 \times (50+1) }{2}

Which gives;

4 \times \sum\limits _{n = 1}^{50} \left  n^2 =  4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}

3  \times\sum\limits _{n = 1}^{50}  n = 3  \times \dfrac{n \times (n+1) }{2} = 3  \times \dfrac{50 \times (51) }{2}

\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3  \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3  \times \dfrac{50 \times (51) }{2}

Therefore, we have;

4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3  \left (\dfrac{50(51) }{2} \right ).

4 0
3 years ago
-1/2(-3y+10) i need help solving this math problem
worty [1.4K]

Answer:

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
M<br> Hurry answer it’s due today
omeli [17]

Answer:

83.55

Step-by-step explanation:

i think

5 0
2 years ago
What is the volume of this cylinder?
Anastasy [175]

Answer:

150.72 mm^3

Step-by-step explanation:

volume = (pi)(r^2)h

volume = 3.14 * (4 mm)^2 * 3 mm

volume = 3.14 * 16 mm^2 * 3 mm

volume = 150.72 mm^3

7 0
3 years ago
Write the equation for the line tangent to the circle x2 + y2 = 29 at the point (2, 5).
oee [108]
X2 + y2 = 29

Center of the circle 
x=0 and y=0

Therefore the slope of the line perpendicular to the tangent line
(y2-y1) / (x2-x1)
(5-0) / (2-0)
5/2
 
 so the slope of the tangent 
 -2/5             

General equation for the line
y = mx + c
if the line satisfies with the point (2,5)
5 = 2m + c

m = -2/5

5 = 2 * (-2/5) + c
c = 5 + (4/5)
c = 29/5

Therefore the equation of the line
y = mx + c
y = (-2/5) m + 29/5 
3 0
3 years ago
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