Answer:
144
Step-by-step explanation:
Jane has 2 times as many books as Jill, so there are 3 parts. Two parts Jane and one part Jill. So, divide 216 by 3 and it's 72, which equals one part. Jane has two parts, so 72 x 2. Jane has 144 books.
(a) Take the Laplace transform of both sides:


where the transform of
comes from
![L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)](https://tex.z-dn.net/?f=L%5Bty%27%28t%29%5D%3D-%28L%5By%27%28t%29%5D%29%27%3D-%28sY%28s%29-y%280%29%29%27%3D-Y%28s%29-sY%27%28s%29)
This yields the linear ODE,

Divides both sides by
:

Find the integrating factor:

Multiply both sides of the ODE by
:

The left side condenses into the derivative of a product:

Integrate both sides and solve for
:


(b) Taking the inverse transform of both sides gives
![y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]](https://tex.z-dn.net/?f=y%28t%29%3D%5Cdfrac%7B7t%5E2%7D2%2BC%5C%2CL%5E%7B-1%7D%5Cleft%5B%5Cdfrac%7Be%5E%7Bs%5E2%7D%7D%7Bs%5E3%7D%5Cright%5D)
I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that
is one solution to the original ODE.

Substitute these into the ODE to see everything checks out:

꙰ Hello there mohammedsaquibali45 ! My Name is ⚝Tobie⚝ and I'm glad you asked! Let me walk you step by step in order to comprehend the question better! ꙰
i
{x}^{2}-5x-10x+50
x
2
−5x−10x+50
ii Collect like terms.
{x}^{2}+(-5x-10x)+50
x
2
+(−5x−10x)+50
iii Simplify.
{x}^{2}-15x+50
x
2
−15x+50
Answer:
0.11069
Step-by-step explanation:
We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.
P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

I hope that works for you!
Assuming the first 5 terms are:
n = 0
n = 1
n = 2
n = 3
n = 4
a) 4n + 4
4(0) + 4 = 4
4(1) + 4 = 8
4(2) + 4 = 12
4(3) + 4 = 16
4(4) + 4 = 20
b) 8n + 3
8(0) + 3 = 3
8(1) + 3 = 11
8(2) + 3 = 19
8(3) + 3 = 27
8(4) + 3 = 35
c) 18 - 3n
18 - 3(0) = 18
18 - 3(1) = 15
18 - 3(2) = 12
18 - 3(3) = 9
18 - 3(4) = 6