well, we'll be using the distance formula twice here.
that point, is on the x-axis, what's the value of "y" at the x-axis? well y = 0, since it's way down at the 0 level, so the point must be (x , 0).
the distance then from (x,0) to (-3,-1) is the same distance as from (x,0) to 1,6).
0.7 can be turned into a fraction which can be 70/100 and 3/4 can be turned into 75/100 so 3/4 would be greater
F(x) = a*x^2 + b*x + c; where a is not 0;
f(-2) = -11 => 4a -2b + c = -11;
f(4) = 13 => 16a +4b + c = 13;
f(6) = 29 => 36a + 6b + c = 29;
You must find a, b, c;
<span><u>3(x-6)=10x+3</u></span>
Expand the left side:
3x-18 = 10x + 3
Subtract 3x from each side:
-18 = 7x + 3
Subtract 3 from each side:
-21 = 7x
Divide each side by 7 :
<u>-3 = x</u>
