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Brilliant_brown [7]
3 years ago
14

13 / 1/4 jrjhdbfhfnfndnsnd

Mathematics
2 answers:
gtnhenbr [62]3 years ago
7 0
The answer would be 52
katovenus [111]3 years ago
6 0
The correct answer is 52
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Find the point on the x-axis that is equidistant from the points (−3,−1) and (1,6)
Klio2033 [76]

well, we'll be using the distance formula twice here.

that point, is on the x-axis, what's the value of "y" at the x-axis?  well y = 0, since it's way down at the 0 level, so the point must be (x , 0).

the distance then from (x,0) to (-3,-1) is the same distance as from (x,0) to 1,6).

\bf \begin{array}{rcllll} \stackrel{\textit{distance from (x,0) to (-3,-1)}}{\sqrt{(-3-x)^2+(-1-0)^2}}&=&\stackrel{\textit{distance from (x,0) to (1,6)}}{\sqrt{(1-x)^2+(6-0)^2}} \\\\\\ (-3-x)^2+(-1-0)^2&=&(1-x)^2+(6-0)^2 \\\\\\ 9+6x+x^2+1&=&1-2x+x^2+36 \\\\\\ x^2+6x+10&=&x^2-2x+37 \end{array} \\\\\\ 6x+10=-2x+37\implies 8x+10=37\implies 8x=27 \\\\\\ x = \cfrac{27}{8}\implies x = 3\frac{3}{8}~\hfill \blacktriangleright \left( 3\frac{3}{8}~,~0 \right) \blacktriangleleft

4 0
4 years ago
Which is greater 0.7 or 3/4
vovangra [49]
0.7 can be turned into a fraction which can be 70/100 and 3/4 can be turned into 75/100 so 3/4 would be greater
3 0
4 years ago
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Find the particular equation of quadratic function containing (-2,-11) (4,13) and (6,29)
Firlakuza [10]
F(x) = a*x^2 + b*x + c; where a is not 0;
f(-2) = -11 => 4a -2b + c = -11;
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You must find a, b, c;
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3 years ago
How To Solve The Equation 3(x-6)=10x+3 ?
kykrilka [37]
<span><u>3(x-6)=10x+3</u></span>

Expand the left side:

3x-18 = 10x + 3

Subtract 3x from each side:

-18 = 7x + 3

Subtract 3 from each side:

-21 = 7x

Divide each side by 7 :

<u>-3 = x</u>

4 0
3 years ago
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What is the area of the figure?<br> 7 in.<br> 8 in.<br> 7 in.<br> 8 in.<br> ,<br> 4 in.<br> 16 in.
Alex17521 [72]

Answer:

Step-by-step explanation:

50

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