<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>
Solution:
It is given that two triangles Δ ABC and Δ X Y Z are similar by Side -Side - Side(SSS) Similarity theorem.
So, the Statement which is given, that is →→∠B ≅ ∠Y and ∠B ≅ ∠Z, is inadequate for similarity criterion by SSS, as these statement are about angles of Triangles,not sides, which can't be true.
So, if the two triangles are Similar by SSS criterion , then the appropriate mathematical statement must be,
⇒
In this problem you will need to use the Pythagorean theorem (c^2=a^2+b^2).
The a and b represents the two edges, while c is the diagonal side and it is called the hypotenuse. Since you already know what the hypotenuse is and what one of the sides already are you just have to use the problem: c^2-a^2=b^2. Then if you plug the data you already have into the problem you will get 10^2-6^2=b^2. That then equals 100-36=b^2. Then you subtract and get b^2=64. Then you square root both sides and you get the answer b=8.
Answer:
<em>a) 15 b) 6 c) -3</em>
Step-by-step explanation:
x - y = 3
a) 5 (x - y) = 5 (3) = 15
b) 2x - 2y = 2 (x - y) = 2 (3) = 6
c) y - x = -1 (x - y) = -1 (3) = -3
