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3 years ago

14

What is the area of the rectangle

1 answer:

Colt1911 [192]3 years ago

6 0

Area is length times width
(x+3)y
then distribute
xy +3y
thats your area

You might be interested in

Which is the value of this expression when m = 3 and n = -5?

Marrrta [24]

The answer is: [C]: " 1/8 " .
_________________________________________________

(6 * 3⁻¹) ⁻³ = (6 / 3¹) ⁻³ = 2⁻³ = 1 / 2³ = 1/8 ; which is answer choice: [C]:

Note that n⁰ =1 ; regardless of what "n" is equal to;
and any value, multiplied by "1", equals that same value.

so "n⁰ " ; which equals "1" ; is simply "canceled out" .
___________________________________________________

7 0

3 years ago

Read 2 more answers

Let f (x) = 1/x<br> and g(x) = x² – 3x. What<br> two numbers are not in the domain of fºg?

iren [92.7K]

For this case we have the following equations:

$f (x) = \frac {1} {x}\\g (x) = x ^ 2-3x$

We must find $(f_ {o} g) (x):$

By definition of composition of functions we have to:

$(f_ {o} g) (x) = f (g (x))$

So:

$(f_ {o} g) (x) = \frac {1} {x ^ 2-3x}$

We must find the domain of f (g (x)). The domain will be given by the values for which the function is defined, that is, when the denominator is nonzero.

$x ^ 2-3x = 0\\x (x-3) = 0$

So, the roots are:

$x_ {1} = 0\\x_ {2} = 3$

The domain is given by all real numbers except 0 and 3.

Answer:

x other than 0 and 3

8 0

3 years ago

Read 2 more answers

The quotient of m and 11 minus 3 as a algebraic expression

PilotLPTM [1.2K]

(m/11) - 3
Doing the quotient first so I put it in parenthesis, then subtract 3

3 0

3 years ago

Assume that BK Call Center receives 2 phone calls in one hour on average. If the department works 10 hours a day receiving the c

MrMuchimi

Using the Poisson distribution, the probabilities are given as follows:

A. 0.0888 = 8.88%.

B. 0.1354 = 13.54%.

C. 0.8646 = 86.46%.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Item a:

10 hours, 2 calls per hour, hence the mean is given by:

$\mu = 2 \times 10 = 20$ .

The probability is P(X = 20), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 20) = \frac{e^{-20}20^{20}}{(20)!} = 0.0888$

Item b:

1 hour, hence the mean is given by:

$\mu = 2$

The probability is P(X = 0), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}2^{0}}{(0)!} = 0.1354$

Item c:

The probability is:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1354 = 0.8646$

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

5 0

2 years ago

You walk 3 miles from your house to the store. At the store you meet up with a friend and walk with her 1 mile back towards your

jenyasd209 [6]

Answer:

2 miles from your house

Step-by-step explanation:

you walked 3 miles to the store so you are now 3 miles away.

you meet a friend and walk 1 mile in the direction of your house.

now there is 2 miles left.

3 - 1 = 2

5 0

3 years ago