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podryga [215]
3 years ago
15

Find the slope of the line passing through each of the following pairs of points. (0, 7), (0, −8)

Mathematics
2 answers:
alexgriva [62]3 years ago
7 0

Hi there!

Step-by-step explanation:

SLOPE=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}

\frac{(-8)-7}{0-0}=\frac{-15}{0}

<u><em>Undefined.</em></u>

<u><em>Slope is -15/0 and 0.</em></u>

<u><em>Final answer is -15/0 and 0.</em></u>

Hope this helps!

Thanks!

Have a nice day! :)

:D

-Charlie

neonofarm [45]3 years ago
3 0
First off,we need to understand the formula of slope:
\frac{y1 - y2}{x1 - x2}
Where y is the y coordinate and x is the x coordinate.

In this case:
\frac{7 - ( - 8)}{0 - 0}   \\ = 7  + 8  \\ = 15

Therefore the answer is 15.

Hope it helps!
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7 0
3 years ago
9. What is 999 x 4 =
zimovet [89]
999 x 4 equals 3,996
7 0
3 years ago
Read 2 more answers
Can you help me out on this question?
astra-53 [7]

Answer:

4. x= 18

Step-by-step explanation:

We solve the problem like this:

Since 3 is proportional to 6 and 9 is proportional to x, we set up a proportion.

3/9 = 6/x  

We then use cross-multiplication to solve for x.

7 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
If g(x)=7x²−4x−3 and h(x)=5x²−12x, find (h∘g)(1)<br><br><br>FIRST BEST ANSWER BRAINLIEST
AURORKA [14]

Answer: See below

Step-by-step explanation:

h\:\circ \:g=h\left(g\left(x\right)\right)

=5\left(7x^2-4x-3\right)^2-12\left(7x^2-4x-3\right)

=5\left(7x^2-4x-3\right)\left(7x^2-4x-3\right)-12\left(7x^2-4x-3\right)

=245x^4-280x^3-130x^2+120x+45-84x^2+48x+36

Simplify:

=245x^4-280x^3-214x^2+168x+81

6 0
3 years ago
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