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kaheart [24]
2 years ago
11

Plzzz i need help helpppppppppppppppppppppp

Mathematics
2 answers:
butalik [34]2 years ago
5 0

Answer:

x+(x-23)

Step-by-step explanation:

The sum of a number

x+

And 23 less than that number

(x-23)

Put it together

x+(x-23)

Stella [2.4K]2 years ago
3 0

Answer:

b is the correct expression

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sarah invests £9600 at a simple interest rate of 8% per year. Work out the value of the investment after 3 years
andre [41]

Answer:

the value of the investment after 3 years=  £11,904

Step-by-step explanation:

sarah invests £9600 at a simple interest rate of 8% per year

number of years = 3

Formula for simple interest

I = P*n* r

P is the initial amount invested= 9600

r is the rate of interest = 8% = 0.08

n = number of years = 3

Now we find interest using formula

I = 9600 * 0.08 * 3= 2304

Interest amount is 2,304

Now we add the interest with the initial amount to get the value of investment after 3 years

9600 + 2304= 11904

6 0
3 years ago
Using the chart above, find the total amount and amount of interest paid in the following compound interest problems.
gizmo_the_mogwai [7]

Answer:

Annually: Total Amount = 1611.76, Interest Amount = 711.76

Semiannually: Total Amount = 1625.50 , Interest Amount = 725.50

Quarterly: Total Amount = 1632.62 , Interest Amount = 732.62

Step by Step Explanation:

We can see from the table that the factor that we need to multiply with 900 in order to get amount for compounded annually is 1.7908477. Therefore, our total amount is 1.7908477*900 = 1611.76 and interest earned is 1611.76-900 = 711.76.

The factor that we need to multiply with 900 in order to get amount for compounded semiannually is 1.8061112. Therefore, our total amount is 1.8061112*900 = 1625.50 and interest earned is 1625.50-900 = 725.50.

The factor that we need to multiply with 900 in order to get amount for compounded semiannually is 1.8140184. Therefore, our total amount is 1.8140184*900 = 1632.62 and interest earned is 1632.62-900 = 732.62.

6 0
3 years ago
Iodine-125 has a half-life of about 60 days. How many milligrams of a 1000 mg sample will remain after 240 days?
Tomtit [17]

240 days is 4 times the half-life, which means that a sample of 1000 mg will decay to

\dfrac{1000}{2^4}=\dfrac{125}2=62.5\,\mathrm{mg}

after 240 days.

3 0
3 years ago
What is the answer is it A. or B. or C. ?
nekit [7.7K]

Answer:

i believe its b

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
HELP 20 POINTS PLZ RAHHHH
schepotkina [342]

Answer:

answer is option D : 42m+12

7 0
3 years ago
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