The reflexive documentary mode focuses on the relationship between the filmmaker and the audience. While expository documentaries set up a specific point of view or argument about a subject and a narrator often speaks directly to the viewer.
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int x=5,y=2,z=9;
int min;
// find the smallest value and assign to min
// if x is smallest
if(x < y && x < z)
// assign x to min
min=x;
// if y is smallest
else if(y < z)
// assign y to min
min=y;
// if z is smallest
else
// assign z to min
min=z;
// print the smallest
cout<<"smallest value is:"<<min<<endl;
return 0;
}
Explanation:
Declare and initialize variables x=5,y=2 and z=9.Then check if x is less than y and x is less than z, assign value of x to variable "min" .Else if value of y is less than value of z then smallest value is y, assign value of y to "min".Else z will be the smallest value, assign its value to "min".
Output:
smallest value is:2
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
