Find the sum: −3/4 and 5 /8

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

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Please solve both with explanation, I’ll give brainliest

DiKsa [7]

1st and 2nd pictures are for finding area and 3rd picture is for finding perimeter

hope you understood well and if not and you can ask again

4 0

3 years ago

In the diagram below, O is circumscribed about quadrilateral DEFG. What is the value of x?

Fofino [41]

Answer:

A. 70

Step-by-step explanation:

The given quadrilateral DEFG is a cyclic quadrilateral.

$\angle F+70\degree=180\degree$ ...opposite angles of a cyclic quadrilateral are supplementary.

$\implies \angle F=180\degree-70\degree$

$\implies \angle F=110\degree$

The sum of angles in a quadrilateral is 360 degrees.

$x-10+70+110+120=360$

$x+290=360$

$x=360-290$

$x=70\degree$

7 0

3 years ago

I know it is basic but I need help 11m+13=m+23

zloy xaker [14]

Answer:

m = 1

Step-by-step explanation:

11m + 13 = m + 23

Get m by itself by subtracting m from both sides.

10m + 13 = 23

Subtract 13 from both sides.

10m = 10

DIvide by 10.

m = 1

8 0

3 years ago

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Parallelogram RSTU is shown.

mixas84 [53]

Answer:

-opposite sides of a parallelogram are congruent.

-definition of a parallelogram

- alternate interior angles are congruent

Step-by-step explanation:

I just did the test

5 0

3 years ago

Read 2 more answers