Answer:
Rearrange the equations that result from use of the Pythagorean theorem.
Step-by-step explanation:
Transversal AB crossing parallel lines AD and BC makes supplementary interior same-side angles A and B. Since A = 90°, B must be 90°. The Pythagorean theorem then applies in the right triangles ABC and ABD.
We can use that theorem to write two expressions for AB^2:
BD^2 -AD^2 = AB^2 = AC^2 -BC^2
The middle expression, AB^2, isn't needed beyond this point. Adding (AD^2 -AC^2) to both sides of the equation gives the desired result:
BD^2 -AC^2 = AD^2 -BC^2
The formula of a slope:
We have the points A(-6, 6) and B(12, 3). Substitute:
Therefore we have 
.
Put the coordinates of the point B to the equation:
<em>add 2 to both sides</em>
Answer:
In other words, how many ways are there to choose
objects from a total of
objects? Just one; take all of them at the same time.
Answer:
- (a) no
- (b) yes
- (c) no
- (d) no
Step-by-step explanation:
"Of the order x^2" means the dominant behavior matches that of x^2 as x gets large. For polynomial functions, the dominant behavior is that of the highest-degree term.
For other functions, the dominant behavior will typically be governed in some other way. Here, the rate of growth of the x·log(x) function is determined by log(x), which has decreasing slope as x increases.
Only answer selection B has a highest-degree term of x^2, so only that one exhibits O(x^2) behavior.
→ 
→ 
![\sqrt{[(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%5D%7D%20)
![\sqrt{[(3-(-4))^{2}+(-1-(-5))^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%283-%28-4%29%29%5E%7B2%7D%2B%28-1-%28-5%29%29%5E%7B2%7D%5D%7D%20)
![\sqrt{[7^{2}+4^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B7%5E%7B2%7D%2B4%5E%7B2%7D%5D%7D%20)
![\sqrt{[49+16]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B49%2B16%5D%7D%20)
