Question

25. angle EFG and angle GFH are a linear pair,

Answer 1

Answer:

m<EFG = $69^{o}$, and m<GFH = $111^{o}$

Step-by-step explanation:

Linear pair angles are two supplementary angles.

Thus,

m<EFG + m<GFH = $180^{o}$

2n + 21 + 4n + 15 = $180^{o}$

collecting like terms, we have:

6n + 36 = $180^{o}$

6n = $180^{o}$ - 36

6n = $144^{o}$

divide both both sides by 6,

n = $24^{o}$

Therefore,

m<EFG = 2n + 21

            = 2 x $24^{o}$ + 21

            = 48 + 21

            = $69^{o}$

m<GFH = 4n + 15

             = 4 x $24^{o}$ + 15

            = 96 + 15

            = $111^{o}$

Thus m<EFG = $69^{o}$, and m<GFH = $111^{o}$