Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,

Taking last two ratio,

Putting the value of BC , AC ,∠A,∠B


≈734.106 miles
Therefore they are 734.106 miles apart.
So assuming that the total =27
r+b=27
r=-5+3b
r=3b-5
subsitute 3b-5 for r in first equation
3b-5+b=27
4b-5=27
add 5
4b=32
divide by 4
b=8
subsitute
b+r=27
8+r=27
subtracct 8
r=19
red=19
blue=8
Answer:
it translates to something i can't say on here ;)
If we add $0.14 until we get $21.64, we would add it 154.572 times. To check this answer and make sure I’m right, do this equation: 0.14 x 154.572, then you would get 21.64.
The correct answer is 154.572 minutes.