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fredd [130]
3 years ago
10

a rectangular field is 50 M long and 30 M broad . find a perimeter b) the length of wire required to fence it thrice c)calculate

area of a rectangular field​
Mathematics
2 answers:
kow [346]3 years ago
8 0

Answer:  b) 160 c) 1500

Step-by-step explanation: b) 50 + 50 + 30 + 30 = 160 c) 50 x 30 = 1500

dexar [7]3 years ago
3 0

Step-by-step explanation:

length \: of \: a \: field \:  = 50m

breadth \: of \: a \: field \:  = 30m

Perimeter \: of \: a \: field \:  = ?

We know,

Perimeter ( p ) = 2 ( l + b )

= 2 ( 50m + 30m )

= 2 × 80 m

= 160 m

The length of a wire required to fence it thrice

= 3 × 160 m

= 480 m

Area ( A ) = l × b

= 50 × 30 m

=  {1500m}^{2}

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58

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360 degrees in a whole circle

360-294=66

66-26=40

x-18=40

40+18=58

5 0
3 years ago
Sophia uses 18 beads to make a necklace. Three sixths of the beads are purple. How many beads are purple?
joja [24]

Answer:

9 beads are purple

Step-by-step explanation:

we know that

To find out how many  beads are purple, multiply the total beads by the fraction of the beads that are purple

so

18(\frac{3}{6})=9\ beads

therefore

9 beads are purple

Another way to solve the problem is convert the fraction in percentage

we have

\frac{3}{6}=\frac{1}{2}=0.50*100=50\%

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50% is 9 beads

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3 years ago
To get pictures taken at
xxMikexx [17]
10x + 25 = $145
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7 0
3 years ago
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A certain motorcycle manufacturer has been building motorcycles for 98 years. Over that period, production has increased steadil
Reika [66]

Answer: The fraction would be 0.53.

Step-by-step explanation:

Since we have given that

r(t)=A.(1.05)^t

where, A is the constant initial production rate

t is the time.

For 98 years, the production rate in motorcycles per year would be

r(98)=A.(1.05)^{98}\\\\r(98)=A.119.27

For 13 years, the production rate in motorcycles per year would be

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So, the fraction of their total production was built during the last 13 years would be

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5 0
4 years ago
It’s late! Please help me asap!
Ede4ka [16]

Answer:

D. x = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Leg <em>a</em> = 8

Leg <em>b</em> = <em>x</em>

Hypotenuse <em>c</em> = 10

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [PT]:                    8² + x² = 10²
  2. Isolate <em>x</em> term:                      x² = 10² - 8²
  3. Exponents:                           x² = 100 - 64
  4. Subtract:                               x² = 36
  5. Isolate <em>x</em>:                               x = 6
3 0
3 years ago
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