Answer:
MATLAB code is given below
Explanation:
% Define the function.
function [ output_args] = removeEvens( input_args)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
%Remove the even number from the array using mod function.
output_args = input_args (mod(input_args,2)~=0);
%Display the message.
disp('odd Values are');
%Display the results.
disp(output_args);
%Terminate the function.
end
Function Call:
%Function Call
inputRowArray = [1,2,3,4,5]
removeEvens(inputRowArray)
Answer:
3.85 out of 4
Explanation:
As 96.1791 out of 100 gives 96.1791% calculated below:
Percentage formula: (Obtained value/total value)*100.......eq(1)
Putting values:
= (96.1791/100)*100
= 96.1791%
Now finding 96.1791% of 4:
Putting values in eq (1):
96.1791% = (Obtained value/4)*100
96.1791/100= (Obtained value/4) (dividing by 100 on both sides)
0.961791 = (Obtained value/4)
4* 0.961791 = Obtained value (multiplying 4 on both sides)
3.847164 = Obtained value
Then 96.1791% of 4 will be equal to: 0.961791 * 4 = 3.847164
Rounding off the answer to 2 decimal places:
=3.85 (As the digit on 3rd decimal place is greater than 5)
Answer:
Option C is the correct option to the following question
Explanation:
Because there are not any limits is required of sending data and packets between host A and host B by the routers and the router permit more than one paths between the hosts for the establishment of the connectivity st two distinct locations in the routing protocol. The router transmits the packets between the hosts that is produced by link-state protocol.
