A jar of dimes and quarters contains $15.25. there are 103 coins in all. how many quarters are in the jar?
1 answer:
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First one
when doing the quadratic equation, we come across something called the determinant
when this is positive, we have 2 real roots
when this is 0, we have 1 real root
whenthis is negative, we have 2 imaginary rots
we want 2imaginary roots so
<0
we have
1x^2-6x+c=0
a=1
b=-6
c=c
<0
<0
square root both sies
36-4c<0
add 4c both sides
36<4c
divide both sides by 4
9<c
c>9
D is the answer (not b or c)
remember
√-1=i
a²-b²=(a-b)(a+b)
we want to do
x^2-(-9)
now we have to take the sqrt of -9
√-9=(√-1)(√9)=(i)(3)=3i
(x)^3-(3i)^2
(x-3i)(x+3i)
B is answer
when doing the quadratic equation, we come across something called the determinant
when this is positive, we have 2 real roots
when this is 0, we have 1 real root
whenthis is negative, we have 2 imaginary rots
we want 2imaginary roots so
we have
1x^2-6x+c=0
a=1
b=-6
c=c
square root both sies
36-4c<0
add 4c both sides
36<4c
divide both sides by 4
9<c
c>9
D is the answer (not b or c)
remember
√-1=i
a²-b²=(a-b)(a+b)
we want to do
x^2-(-9)
now we have to take the sqrt of -9
√-9=(√-1)(√9)=(i)(3)=3i
(x)^3-(3i)^2
(x-3i)(x+3i)
B is answer
Answer:
the y coordinate is 5
Step-by-step explanation:
In the figure attached, the directed line segment is shown.
J is located at (-3, 1) and K is located at (-8, 11)
run: x2 -x1 = -8 - (-3) = -5
rise: y2 - y1 = 11 - 1 = 10
Taking J as reference, the coordinate of the point that divides the directed line segment from J to k into a ratio of 2:3 is:
c = 2/(2+3) = 0.4
(x1 + c*run, y1 + c*rise)
(-3 + 0.4*-5, 1+0.4*10)
(-5, 5)
