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liberstina [14]
2 years ago
11

Each cone of the hourglass has a height of 12 millimeters. The total height of the sand within the top portion of the hourglass

is 47 millimeters. The radius of both the cylinder and cone is 4 millimeters. Sand drips from the top of the hourglass to the bottom at a rate of 10π cubic millimeters per second. How many seconds will it take until all of the sand has dripped to the bottom of the hourglass? (4 points)
Mathematics
1 answer:
Harman [31]2 years ago
7 0

The solution would be like this for this specific problem:

Volume of a cylinder = pi * r^2 * h 

Volume of a cone = 1/3 * pi * r^2 * h 

Total Height = 47

Height of the cone = 12

Height of the cylinder = 35

If the top half is filled with sand, then:

volume (sand) = pi * 4^2 * 36

volume (cone) =  1/3 * pi * 4^2 * 12

Total volume = 1960.353816 cubic millimeters

353816 / (10 * pi) = 62.4 seconds.

It will take 62.4 seconds until all of the sand has dripped to the bottom of the hourglass.

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Step-by-step explanation:

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What is the result of isolating y2 in the equation below? 9x2 + 7y2 = 42
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1.5( x + 4) -3 = 4.5 ( x - 2 )
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Answer:

Step-by-step explanation:

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4 = x <======

6 0
2 years ago
The radius of a circle is 8 feet. What is the area of sector bounded by a 90° arc?
Lera25 [3.4K]

Since 90 degree is 1/4 of a circle, the area will be 1/4 th area of the full circle.

The radius is given by, r = 8 ft, therefore, the area of the full circle is,

\begin{gathered} A=\pi\times r^2 \\ A=3.14\times8^2=200.96ft^2 \end{gathered}

Therefore, the area of the sector is,

A^{\prime}=\frac{1}{4}\times200.96ft^2=50.24ft^2\begin{gathered} A^{\prime}=\frac{\theta}{360}\times\pi\times r^2 \\ \text{ =}\frac{\text{90}}{360}\times\pi\times8^2 \\ \text{ =}\frac{1}{4}\pi\times64=16\pi \end{gathered}

4 0
1 year ago
There were 5 1/3 jars of pickles. Ann and her friends ate 1 1/3 jars. How many jars of pickles are left? *
densk [106]

Answer:5/3 jars left

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