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Ilia_Sergeevich [38]
3 years ago
11

Which scenario best matches the linear relationship expressed in the equation y = 13.50x + 300? 1. Bobby has $300 in the yearboo

k fund and spends $13.50 on each yearbook. 2. Bobby has $13.50 in the yearbook fund and spends $300 on each yearbook. 3. Bobby has $300 in the yearbook fund and earns $13.50 for each yearbook sold. 4. Bobby has $13.50 in the yearbook fund and earns $300 for each yearbook sold.
Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0

Answer:

Choice 3: Bobby has $300 in the yearbook fund and earns $13.50 for each yearbook sold.

Step-by-step explanation:

From the equation y = 13.50x + 300, we can derive that:

300 is the initial value, or y-intercept.

13.50 is the rate of change, or slope.

Let's go through each choice and eliminate:

1. Incorrect, because spending $13.50 on each yearbook would mean a negative slope.

2. Incorrect, because the initial value is $300, not $13.50.

3. Correct, because $300 is the initial value and earning $13.50 means a positive slope.

4. Incorrect, because the initial value should be $300.

Therefore, choice 3 is the correct scenario.

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A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m
arsen [322]

Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let <em>X</em> = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.

The sample of employed individuals selected is of size, <em>n</em> = 225.

An individual holding multiple jobs is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.

Conditions of Normal approximation to Binomial are:

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  • n (1 - p) ≥ 10

Check the conditions as follows:

np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10

The distribution of the proportion of individuals who hold multiple jobs is,

p\sim N(p, \frac{p(1-p)}{n})

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

P(p

*Use a <em>z</em>-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

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Let's subtract the eight DVDs Joe received as gifts, because he didn't buy them on his own.

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