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ElenaW [278]
3 years ago
12

The solid shown is constructed from a cylinder and two hemispheres with dimensions as shown. Find the volume of this solid to th

e nearest cubic unit.

Mathematics
1 answer:
JulsSmile [24]3 years ago
7 0

Answer:

Volume of solid = 10,466.67 unit² (Approx)

Step-by-step explanation:

Given:

Height of cylinder = 20 unit

Radius of hemisphere = 10 unit

Radius of cylinder = 10 unit

Two hemisphere = 1 sphere

Find:

Volume of solid.

Computation:

Volume of solid = Volume of cylinder + Volume of sphere

Volume of solid = πr²h + 4 /3[πr]³

Volume of solid = π[r²h + (4 /3)(r)³]

Volume of solid = 3.14[(10)²(20) + (4 /3)(10)³]

Volume of solid = 3.14[2,000 + 1333.34]

Volume of solid = 10,466.67 unit² (Approx)

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This question is not valid because the gift card is only 90 pounds. You states that the Coffee she bought was 553 dollars. This means she will have negative profit, therefore this question is not states correctly.

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3 years ago
Triangle PQR is a right triangle.
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Answer:

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180 - 92 = 88

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Step-by-step explanation:

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Suppose that the population​ P(t) of a country satisfies the differential equation dP/dt = kP (600 - P) with k constant. Its pop
jeka94

Answer:

The country's population for the year 2030 is 368.8 million.

Step-by-step explanation:

The differential equation is:

\frac{dP}{dt}=kP(600 - P)\\\frac{dP}{P(600 - P)} =kdt

Integrate the differential equation to determine the equation of P in terms of <em>t</em> as follows:

\int\limits {\frac{1}{P(600-P)} } \, dP =k\int\limits {1} \, dt \\(\frac{1}{600} )[(\int\limits {\frac{1}{P} } \, dP) - (\int\limits {\frac{}{600-P} } \, dP)]=k\int\limits {1} \, dt\\\ln P-\ln (600-P)=600kt+C\\\ln (\frac{P}{600-P} )=600kt+C\\\frac{P}{600-P} = Ce^{600kt}

At <em>t</em> = 0 the value of <em>P</em> is 300 million.

Determine the value of constant C as follows:

\frac{P}{600-P} = Ce^{600kt}\\\frac{300}{600-300}=Ce^{600\times0\times k}\\\frac{1}{300} =C\times1\\C=\frac{1}{300}

It is provided that the population growth rate is 1 million per year.

Then for the year 1961, the population is: P (1) = 301

Then \frac{dP}{dt}=1.

Determine <em>k</em> as follows:

\frac{dP}{dt}=kP(600 - P)\\1=k\times300(600-300)\\k=\frac{1}{90000}

For the year 2030, P (2030) = P (70).

Determine the value of P (70) as follows:

\frac{P(70)}{600-P(70)} = \frac{1}{300} e^{\frac{600\times 70}{90000}}\\\frac{P(70)}{600-P(70)} =1.595\\P(70)=957-1.595P(70)\\2.595P(70)=957\\P(70)=368.786

Thus, the country's population for the year 2030 is 368.8 million.

3 0
4 years ago
If f(x)f(x) is an exponential function where f(1.5)=5f(1.5)=5 and f(7.5)=79f(7.5)=79, then find the value of f(3)f(3), to the ne
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Answer: 7.93

Step-by-step explanation:

Given

f(x) is an exponential function. Suppose f(x) is ae^{bx}

f(1.5)=5\ \text{and}\ f(7.5)=79

\Rightarrow 5=ae^{1.5b}\\\Rightarrow \ln 5=\ln a-1.5b\quad \ldots(i)

Similarly,

\Rightarrow 79=ae^{7.5b}\\\Rightarrow \ln(79)=\ln a+7.5b\quad \ldots(ii)

Subtract (i) and (ii)

\Rightarrow \ln (79)-\ln (5)=9b\\\Rightarrow \ln (\frac{79}{5})=9b\\\\\Rightarrow b=\dfrac{\ln (\frac{79}{5})}{9}\\\\\Rightarrow b=0.3066

Insert the value of b

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So, the function becomes

\Rightarrow f(x)=3.16e^{0.3066b}

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