All categories

3 years ago

Math... please help :(

Mathematics

2 answers:

NeX [460]3 years ago

8 0

B! Sorry if im wrong..:(

irinina [24]3 years ago

6 0

Answer: A ) Angle-Angle-Side

You might be interested in

H(1)=9<br> h(n)=h(n-1)·1/9<br> h(3)=?

Amiraneli [1.4K]

Answer:

1/9

Step-by-step explanation:

h1 = 9

h2 = h1 × 1/9 = 9 × 1/9 = 1

h3 = h2 × 1/9 = 1 × 1/9 = 1/9

3 0

3 years ago

You are ordering packaging for a product. Should you be more concerned with volume or surface area? Explain

Rama09 [41]

If you are ordering packaging for a product you would be more concerned with volume as the volume would tell you how much space something takes up so how much packaging you need to order for it.

3 0

4 years ago

Read 2 more answers

An airplane travels about 500 miles per hour. The function d(t) = 500t represents the number of miles traveled in t hours. How f

vaieri [72.5K]

Answer:

1750 miles

Step-by-step explanation:

500*3.5=1750

3 0

3 years ago

Determine and state the measure of angle F

mezya [45]

Answer:

∠ F = 94°

Step-by-step explanation:

The opposite angles of the quadrilateral are supplementary, thus

∠ D + ∠ F = 180°, that is

86° + ∠ F = 180° ( subtract 86° from both sides )

∠ F = 94°

4 0

3 years ago

Read 2 more answers

plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

4 years ago