All categories

3 years ago

According to a certain country’s department of education, 40.0% of 3-year-olds are enrolled in day care.

Mathematics

1 answer:

vladimir1956 [14]3 years ago

7 0

Given parameters:

Percentage of enrollment of 3-year-olds = 40%

Unknown:

Probability that a randomly selected 3-year-old is enrolled in a day care = ?

Probability is the likelihood of an event to occur.

Probability = $\frac{Possible outcome}{Total out come}$

In this problem, 40% of the total number of 3-year-olds are enrolled in a day care.

We can say, out of every 100 3-year-olds, 40 of them will enroll in day care.

The possible enrollment is 40 and the total is 100;

Input the parameters and solve;

Probability = $\frac{40}{100}$ = $\frac{2}{5}$

The probability that any randomly selected 3 year old is enrolled in day care is $\frac{2}{5}$

You might be interested in

This is slightly urgent. Does anyone know how to cross multiply and divide 1/5 and 20/x? It would look like this if you need the

kumpel [21]

Answer:

1/5 * 20/x. first do 1× x then do 5×20 and you will get 1x/100

Step-by-step explanation:

sorry this is all i know

6 0

2 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

What kind of shape is this? O A. Not a polygon O B. Triangle O c. Quadrilateral O D. Pentagon

Sophie [7]

Answer:

Add the picture please :) i will go on your page and answer when you add the image. Remember to always double check if you have the image clipped on whenever you ask something that needs an image, thank you.

6 0

3 years ago

in a circle, a 60° sector has an area of a 36π cm^2. find the radius of the circle. round your answer to the nearest whole centi

hammer [34]

Area of circle = $\frac{ \theta }{360^o} \times \pi r^2 \\ 36 \pi = \frac{60^o}{360^o} \times \pi r^2 \\ r^2=216 \\ r= \sqrt{216} =14.70 \ cm \\ r=15 \ cm \ to \ the \ nearest \ whole \ centimeter.$

3 0

3 years ago

This is on claskick 7th grade 7(m +2n)<br> 7( )+ 7 ( )

mixer [17]

Answer: 7(m+2m) is equal to 7(m) + 7(2m)

5 0

3 years ago