Answer:
11/18
Step-by-step explanation:
The desired probability is the sum of ...
... (probability of choosing a coin) × (p(heads) on that coin)
Since the coins are chosen at random, we assume the probability of choosing a given coin is 1/3. Then ...
... p(heads) = (1/3)·(1/2) + (1/3)·1 + (1/3)·(1/3) = 1/6 + 1/3 + 1/9 = (3 +6 + 2)/18
... p(heads) = 11/18
I set x-3 and 3x-13 equal to each other and then got x equal to 5. So, I believe the correct answer would be C.) 5
The trick question is that you can’t effect an unknown value because you don’t know what number it is, it has to be a known value, there is nothing that you can do to figure it out, so it’s unknown and cannot be effected.
Please show a picture so that I can help you
The correct answer would be D, the median 86.5.
In this set of data most of the values are in the 80's or 90's. There is only 1 number that is outside of this range, that is the value 0. It is an outlier.
When we have an outlier, the median generally gives us the better measure of central tendency.