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3 years ago

What is the answer to 846 divided 353

Mathematics

2 answers:

tamaranim1 [39]3 years ago

7 0

Answer:

2.396600567

Step-by-step explanation:

BigorU [14]3 years ago

6 0

2.39660057 this is the answer

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9+3.5g=11-0.5g brainliest to whoever gives steps

kow [346]

Answer:

The answer is g = 0.5

Step-by-step explanation:

1. Your equation is :

9+3.5g=11-0.5g

2. First, multiply both sides by ten

9 * 10 + 3.5 * 10 = 11 * 10 - 0.5 * 10

3. Next we refine the equation

90 + 35g = 110 - 5g

4. Now, lets subtract 90 from both sides

90 + 35g - 90 = 110 - 5g - 90

5. Simplify

35g + 5g = -5g + 20 + 5g

6. We then add 5g to both sides

35g + 5g = -5g + 20 + 5g

7. Simplify again

40g = 20

8. Now, divide both sides by 40

40g/40 = 20/40

9. And finally, simplify once again to get your final answer.

g = 1/2 or 0.5

I hope this helped :)

7 0

3 years ago

The table below shows data from a survey about the amount of time students spend doing homework each week. The students were in

nadezda [96]

Answer:

The correct option is;

Both spreads are best described by the standard deviation

Step-by-step explanation:

The given information are;

, College High School

High, 20 20

Low, 6 3

Q₁, 8 5.5

Q₃, 18 16

IQR, 10 10.5

Median, 14 11

Mean, 13.3 11

σ, 5.2 5.4

Checking for outliers, we have

College

Q₁ - 1.5×IQR gives 8 - 1.5×10 = -7

Q₃ + 1.5×IQR gives 18 + 1.5×10 = 33

For high school

Q₁ - 1.5×IQR gives 5.5 - 1.5×10.5 = -10.25

Q₃ + 1.5×IQR gives 16 + 1.5×10.5 = 31.75

Therefore, there are no outliers and the data is representative of the population

From the data, for the college students, it is observed that the difference between the mean, 13.3 and Q₁, 8, and between Q₃, 18 and the mean,13.3 is approximately the standard deviation, σ, 5.2

The difference between the low and the high is also approximately 3 standard deviations

Therefore the college spread is best described by the standard deviation

Similarly for the high school students, the IQR is approximately two standard deviations, the difference between the mean, 11 and Q₁, 5.5, and between Q₃, 16 and the mean,11 is approximately the standard deviation, σ, 5.4

Therefore the high school spread is also best described by the standard deviation.

4 0

3 years ago

In one lottery game, contestants pick five numbers from 1 through 23 and have to match all five for the big prize (in any order)

mihalych1998 [28]

The probability of matching three out of five numbers is 153/33649

<h3>How to determine the probability?</h3>

The numbers are given as:

1 to 23

There are five matching numbers

The probability of getting a match is:

p = 5-k/n where k = 0, 1, 2

While the complement probability is

q = (n - 2)/n

Using the above formulas, the probability of getting from 5 is:

P = 5/23 * 4/22 * 3/21 * 18/20 * 17/19

Evaluate the product

P = 153/33649

Hence, the probability of matching three out of five numbers is 153/33649