Question

In the freshman class, 62% of the students take math, 49% take science, and 38% take both science and math. what percentage takes at least one science or math course?

Answer 1

we are given

62% of the students take math

so,

$n(M)=62$

49% take science

$n(S)=49$

38% take both science and math

n(M∩S)=38

now, we can use union formula

n(M∪S)=n(M)+n(S) -n(M∩S)

now, we can plug values

and we get

n(M∪S)=62+49 -38

n(M∪S)=73

so,

the percentage takes at least one science or math course is 73%..........Answer

Answer 2

P(M)=0.62,P(S)=0.49,P(S  and M)=0.39

From the above

P(m)=0.62,p(s)=0.49,p(s and m)=0.38

The percentage of students that takes at least one science or math

P(s and m)=p(s)+p(m)-p(s and m)

=0.49+0.62-0.38

=73