How do you solve 9 - x = 10 using algebraic operations?

Mathematics

1 answer:

vfiekz [6]3 years ago

6 0

$9 - x = 10\\
-x=1\\
x=-1$

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H(x)=4x+4 find h(3b)

Lubov Fominskaja [6]

Answer:

h(3b)=12b+4

another answer

h(3b)=4(3b+1)

Step-by-step explanation:

h(x)=4x+4

h(3b)=4(3b)+4

h(3b)=12b+4

if need to simplify..then:

h(3b)=4(3b+1)

4 0

3 years ago

Anyone help please I need it

andreev551 [17]

Answer:

$-10+i\sqrt{2}$

Step-by-step explanation:

One is given the following expression:

$\sqrt{4}-\sqrt{-98}-\sqrt{144}+\sqrt{-128}$

In order to simplify and solve this problem, one must keep the following points in mind: the square root function ( $\sqrt{}$ ) is a way of requesting one to find what number times itself equals the number underneath the radical sign. One must also remember the function of taking the square root of a negative number. Remember the following property: ( $\sqrt{-1}=i$ ). Simplify the given equation. Factor each of the terms and rewrite the equation. Use the square root property to simplify the radicals and perform operations between them.