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3 years ago

Given the Standard Form of linear equation 5x - 2y = 10, find its x-intercept and y-intercept: (show your work)

Mathematics

1 answer:

Rzqust [24]3 years ago

3 0

We have that
5x - 2y = 10

we know that

Part A)
the x-intercept is when y=0
then
5x - 2y = 10------> 5x=10--------> x=10/5------> x=2

the answer Part A) is
the x intercept is the point (2,0)

Part B)
the y-intercept is when x=0
then
5x - 2y = 10------> -2y=10------> y=-10/2-----> y=-5

the answer Part B) is
the y intercept is the point (0,-5)

see the attached figure

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What is the apparent slope of the line graphed below

maria [59]

I think the answer would be -2.5 because 0-5=-5 and 4-2=2 you subtract the perfect points X1-x2 with y2-y1

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3 years ago

A video game system and several games are sold for $700. The cost of the games is three times as much as cost of the system. Fin

soldier1979 [14.2K]

Answer:

cost of system is $175 and cost of the games is $525

Step-by-step explanation:

Let us take the cost of the system to be X.The games cost 3 times as much as the system and are therefore given 3X. The total cost of the system and the games is $700.Therefore,we form the equation 3X+X=$700.Meaning that 4X=$700 and X is equal to $175.The cost of the system is X therefore it is $175 and the cost of the games is 3X and is therefore $525.

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2 years ago

Help me out please? chapter : exponents and powers

belka [17]

Answer:

$\frac{125}{27}$

Step-by-step explanation:

$\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}$

Lets expand all the composite numbers into prime numbers.

$=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}$

Lets cancel $2^{-4}$ from numerator and denominator.

$=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}$

Using laws of exponents , lets solve this.

$=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}$

$=> \frac{3^{-3} \times 5^{1}}{5^{-2}}$

$=> 3^{-3} \times 5^{[1 - (-2)]}$

$=> 3^{-3} \times 5^{3}$

$=> \frac{5^3}{3^3} = \frac{125}{27}$

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2 years ago

Read 2 more answers

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AlladinOne [14]

The width is 16 and the length is 20

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2 years ago

What is the factored form of the expression. (2n^2 + 5n + 3) (4n - 5)

7nadin3 [17]

So firstly, the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.

So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:

$(2n^2 + 2n + 3n + 3)(4n - 5)$

Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:

$(2n(n+1)+3(n+1))(4n-5)$

Now we can rewrite this expression as $(2n+3)(n+1)(4n-5)$ , which is your final answer.

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3 years ago