Answer:
It is shifted 4 units down
Answer:
(5 - x)/7 + (x + 4)/2
not rly a simlification but it changes it?
Hope This Helps!!!
Answer:
36 feet
Step-by-step explanation:
Given
![h(t) = -16t^2 + 48t](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%2048t)
Required
Determine the maximum height attained
First, calculate the time to reach maximum height;
In a quadratic equation;
![y = ax^2 + bx + c](https://tex.z-dn.net/?f=y%20%3D%20ax%5E2%20%2B%20bx%20%2B%20c)
The maximum is:
![x = -\frac{b}{2a}](https://tex.z-dn.net/?f=x%20%3D%20-%5Cfrac%7Bb%7D%7B2a%7D)
So, we have:
![t = -\frac{b}{2a}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7Bb%7D%7B2a%7D)
Where
![a = -16; b = 48](https://tex.z-dn.net/?f=a%20%3D%20-16%3B%20b%20%3D%2048)
So:
![t = -\frac{b}{2a}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7Bb%7D%7B2a%7D)
![t = -\frac{48}{2 * -16}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7B48%7D%7B2%20%2A%20-16%7D)
![t = -\frac{48}{-32}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7B48%7D%7B-32%7D)
![t = \frac{48}{32}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B48%7D%7B32%7D)
![t = 1.5](https://tex.z-dn.net/?f=t%20%3D%201.5)
The maximum height is at: ![t = 1.5](https://tex.z-dn.net/?f=t%20%3D%201.5)
So, we have:
![h(t) = -16t^2 + 48t](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%2048t)
![h_{max}=-16 * 1.5^2 + 48 * 1.5](https://tex.z-dn.net/?f=h_%7Bmax%7D%3D-16%20%2A%201.5%5E2%20%2B%2048%20%2A%201.5)
![h_{max}=36](https://tex.z-dn.net/?f=h_%7Bmax%7D%3D36)
It would be three feet. Hope this helps.
Answer:
$393.60
Step-by-step explanation: