Answer:
93.25% probability that they have taken this steroid
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Positive test
Event B: Taking the steroid.
Suppose the probability of an athlete taking a certain illegal steroid is 10%.
This means that 
Given that the athlete has taken this steroid, the probability of a positive test result is 0.995.
This means that 
Positive test:
99.5% of 10%(If the athlete has taken).
100-99.2 = 0.8% of 100-10 = 90%(Athlete has not taken)
Then

Given that a positive test result has been observed for an athlete, what is the probability that they have taken this steroid

93.25% probability that they have taken this steroid
Answer:
y -3 = (-1/2)(x - 5)
Step-by-step explanation:
Slope of line: Notice that if we go from 7 to 5, the 'run' is -2 and the corresponding 'rise' from 2 to 3 is 1. Thus, the slope is m = -1/2.
Using m = -1/2 and the point (5, 3), we write the equation of this line in point-slope form as:
y -3 = (-1/2)(x - 5)
Figure 2 & 4
Figure 2 is scaled 2x the size of the letter A
Figure 4 is 2x smaller than the size of the letter A
dy/dx = 2xy
dy/y = (2x)dx
INT(1/y)dy = INT(2x)dx
ln y + c = x^2 + d
ln y = x^2 + constant
y = e^(x^2 + constant)
1 = e^constant ... so constant=0 ... so y = e^(x^2)
Verification:
y = e^(x^2)
dy/dx = 2x*e^(x^2) = 2xy
<span>and e^(0^2) = e^0 = 1
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Answer:
Slope: 1/4
Step-by-step explanation: