$864 all you had to do was multiply 216 by 4 and 380 by 4 to get 1520 and 656 subtract that to get 864
Mean is 30,median is 30.5,mode is 31.
A² + b² = c²
5² + 8² = x²
x² = 25 + 64
x² = 89
x = √89
x = 9.43
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
tanx = 
Consider the left side
← divide terms on numerator/denominator by cotA
= 
= 
= right side , thus proven
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.