3x - 1 = 3x + 1
subtract 3x from both sides to get (-1 = 1). This is a false statement so it is: CONTRADICTION
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4x - 11 = 7
add 11 to both sides and then divide both sides by 4 to get 
. This statement is true only when x = 
so it is: CONDITIONAL
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2 - 8x = 2 - 8x
add 8x to both sides to get (2 = 2). This is a true statement so it is: IDENTITY
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x + 1 = -x + 4
add x to both sides, subtract 1 from both sides, and divide both sides by 2 to get 
. This statement is true only when x = 
so it is: CONDITIONAL
Answer: B, A, C, A
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0
As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81
Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2
So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2
A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.
3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.
So 2k^2 = 9 + 3k have two rational solutions (Option B).
Hope this Helps! :)
Answer:
-1
Step-by-step explanation:
Let the points be <u>(0, a)</u> and <u>(a, 0)</u> (As it mentions the intercepts are equal)
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Applying slope formula :
⇒ m = 0 - a / a - 0
⇒ m = -a/a
⇒ <u>m = -1</u>
Answer:
<h3>The answer is - 6</h3>
Step-by-step explanation:
f(X)=3x-12
To find f(2) substitute the value in the bracket which is 2 into f(x)
That's
f(2) = 3(2) - 12
= 6 - 12
= - 6
Hope this helps you
