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Georgia [21]
3 years ago
15

Iready question 8 which graph does not represent a function​

Mathematics
1 answer:
kondaur [170]3 years ago
5 0

Answer:

The one that makes a circle

Step-by-step explanation:

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Reposting becuase it want let me edit my last one and somebody spam answered it.
harkovskaia [24]

Answer:

5

5Step-by-step explanation:

If you use the distance formula you can solve it pretty easily. The distance formula is:

d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2} \\

The two points you want are A and D. A is (-1, -4) and D is (3, -1). Plug that into the formula...

d = \sqrt{(3 - (-1))^2 + (-1 - (-4))^2}

d = \sqrt{4^2 + 3^2}

d = \sqrt{16 + 9}

d = \sqrt{25}

5

I can solve it in a different way if you want me to.

8 0
3 years ago
Find the area of a rectangle that has a base of (4a) cm and a height (2a + b)
MArishka [77]

Answer:

area = 8a^2 +4ab

Step-by-step explanation:

Area = (4a)(2a + b)

= 8a^2 +4ab

7 0
4 years ago
Read 2 more answers
A motorboat that travels with a speed of 20 km/hour in still water has traveled 20 km against the current and 180 km with the cu
Gala2k [10]
Recall your d = rt.  distance = rate * time.

let's say the speed of the current is "c".

keeping in mind that, when the boat is going against the current, the boat is not really going at 2kmh, but instead at " 20 - c ", because the current is subtracting speed from it.

Likewise when is going with the current, is going at a speed of " 20 + c ".

if the boat took say "t" hours on the way over, on the way back it took the slack from the whole 8 hours and "t", namely it took " 8 - t " hours.

\bf \begin{array}{lccclll}
&\stackrel{km}{distance}&\stackrel{kmh}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{against the current}&20&20-c&t\\
\textit{with the current}&180&20+c&8-t
\end{array}
\\\\\\
\begin{cases}
20=(20-c)(t)\implies \frac{20}{20-c}=t\\
180=(20+c)(8-\stackrel{\downarrow }{t})\\
--------------\\
180=(20+c)\left( 8- \stackrel{\downarrow }{\frac{20}{20-c}}\right)
\end{cases}
\\\\\\
180=(20+c)\left( \cfrac{(160-8c)-20}{20-c} \right)

\bf 180=(20+c)\left( \cfrac{140-8c}{20-c} \right)\implies 180(20-c)=(20+c)(140-8c)
\\\\\\
3600c-180c=2800-160c+140c-8c^2
\\\\\\
3600c-180c=2800-20c-8c^2
\\\\\\
3600c-180c-2800+20c+8c^2=0\implies 8c^2-160c+800=0
\\\\\\
c^2-20c+100=0\implies (c-10)(c-10)=0\implies \boxed{c=10}
8 0
3 years ago
Write True or False:
Leokris [45]

Step-by-step explanation:

2. is false next answer by next person

5 0
3 years ago
complete the square to rewrite y=x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimium and give its c
artcher [175]

The vertex form of the Quadratic equation is y =  (x-3)^{2} +5. The vertex is (3, 5), which is a maximum point.

<h3>what is a quadratic equation?</h3>

A quadratic equation is an algebraic equation with the power of its variable 2.

it can be written in standard form which is called vertex form or in the general form.

Analysis:

y = x^{2} -6x +14

y = x^{2} -6x +9 +5

Simplifying this perfect square expression y = x^{2} -6x +9

y  = x^{2} -3x -3x +9

y = x(x-3) -3(x-3) + 5

y = (x-3)(x-3) +5

y = (x-3)^{2} + 5

In conclusion, the Vertex form of the equation is y = (x-3)^{2} + 5

Learn more about quadratic equation: brainly.com/question/1214333

#SPJ1

6 0
2 years ago
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